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Lesson14.mw

ORDINARY DIFFERENTIAL EQUATIONS POWERTOOL

Lesson 14 -- Euler's Method

Prof. Douglas B. Meade

Industrial Mathematics Institute

Department of Mathematics

University of South Carolina

Columbia, SC 29208

URL:   http://www.math.sc.edu/~meade/

E-mail: meade@math.sc.edu

Copyright  2001  by Douglas B. MeadeAll rights reserved

-------------------------------------------------------------------

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Outline of Lesson 14

14.A Explicit Implementation of Euler's Method

                14.A-1 Example 1

                14.A-2 Example 2

14.B dsolve and Euler's Method

                14.B-1 Example 1 (revisited)

                14.B-2 Example 2 (revisited)

14.C Example 3

>

Initialization

> restart;

> with( DEtools ):

> with( plots ):

Warning, the name changecoords has been redefined

> interface( rtablesize=25 );

10

>

14.A Explicit Implementation of Euler's Method

Euler's method for the solution of a first-order IVP

dy/dx = F(x, y(x)) ,     y(x[0]) = y[0]

can be summarized by the formulae

 x[n+1] = x[n]+h                   

 y[n+1] = y[h]+h*F(x[n], y[n])  

where h is the stepsize.

A simple implementation of Euler's method that accepts the function F, initial time x[0] , initial position y[0] , stepsize h , and number of steps N as input would be

> Euler0 := proc( F, x0, y0, h, N )

>  local i, L, X;

>  X := evalf( < x0 | y0 > );

>  L := X;

>  for i from 1 to N do

>    X := X + < h | h*F(X[1],X[2]) >;

>    L := L, X;

>  end do;

>  return < L >;

> end proc:

>

As a test, compute the Euler's Method solution to

dy/dx = -2*y ,   y(0) = 1

on the interval [0, 1] with h = 0.1.

> Euler0( (x,y)->-2*y, 0, 1, 0.1, 10 );

Matrix([[0., 1.], [.100000000000000004, .800000000000000042], [.200000000000000010, .640000000000000014], [.300000000000000042, .512000000000000010], [.400000000000000022, .409600000000000020], [.5000...

>

A more sophisticated implementation of Euler's method would accept as input the ODE, the initial condition, the interval on which the solution should be computed, and the number of steps. In this case, the implementation could appear as

> Euler := proc( ode, ic, domain, N )

>  local h, i, t, y, F, L, X;

>  t := lhs(domain);

>  y := op(0,lhs(ic));

>  h := ( op(2,rhs(domain))-op(1,rhs(domain)) )/N;

>  F := unapply( subs( y(t)=_y, solve( ode, diff(y(t),t) ) ), (t,_y) );

>  X := evalf( < op(lhs(ic)) | rhs(ic) > );

>  L := X;

>  for i from 1 to N do

>    X := X + < h | h*F(X[1],X[2]) >;

>    L := L, X;

>  end do;

>  return < <t|y>, L >

> end proc:

>

14.A-1 Example 1

The approximate solution to the IVP

> ode1 := diff( y(x), x ) = -2*y(x);

> ic1 := y(0)=1;

ode1 := diff(y(x), x) = -2*y(x)

ic1 := y(0) = 1

>

on the interval [0, 1] by Euler's Method with 10 subdivisions would be obtained with the command

> Euler( ode1, ic1, x=0..1, 10 );

Matrix([[x, y], [0., 1.], [.100000000000000004, .800000000000000042], [.200000000000000010, .640000000000000014], [.300000000000000042, .512000000000000010], [.400000000000000022, .409600000000000020]...

>

14.A-2 Example 2

For a second example, use Euler's Method with N = 2, 4, and 8 subdivisions to find an approximate value for y(2) where the IVP is

> ode2 := diff( y(t), t )*sin(t) + y(t) = 3;

> ic2 := y(1)=2;

ode2 := (diff(y(t), t))*sin(t)+y(t) = 3

ic2 := y(1) = 2

>

and the parameters for the numeric solution are

> a2 := 1;

> b2 := 2;

> N2 := [ 2, 4, 8 ];

a2 := 1

b2 := 2

N2 := [2, 4, 8]

>

The three stepsizes to be used appear in the list

> H2 := map( n->(b2-a2)/n, N2 );

H2 := [1/2, 1/4, 1/8]

>

and the results of the calculations are obtained via

> for k from 1 to 3 do
 sol2 := Euler( ode2, ic2, t=a2..b2, N2[k]);

 Y2[k] := sol2[N2[k]+2,2];

 print(` Y2`[k] = Y2[k]);

od:

>

` Y2`[1] = 2.79760832319999996

` Y2`[2] = 2.71059958021999980

` Y2`[3] = 2.67742503876000048

>

Alternatively, these results are summarized in the following table.

> v0 := < 'h'   | 'N'   | 'Y(2)' >:

> v1 := < H2[1] | N2[1] | Y2[1]  >:

> v2 := < H2[2] | N2[2] | Y2[2]  >:

> v3 := < H2[3] | N2[3] | Y2[3]  >:

> < v0, v1, v2, v3 >;

Matrix([[h, N, Y(2)], [1/2, 2, 2.79760832319999996], [1/4, 4, 2.71059958021999980], [1/8, 8, 2.67742503876000048]])

>

Implementations of Euler's Method for a first-order system are not significantly different or more difficult, but will not be considered at this time.

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14.B dsolve and Euler's Method

While it is not difficult to implement Euler's Method in Maple, there is no real reason to do so. The dsolve command can be used to obtain approximate solutions to IVPs for first-order ODEs, including systems.

To illustrate, revisit Examples 1 and 2.

14.B-1 Example 1 (revisited)

When an explicit table of values is needed, it is necessary to provide a list of values of the independent variable at which the approximate solution should be reported.

In Example 1, the numeric parameters were

> x0 := 0;

> h1 := 0.1;

> N1 := 10;

x0 := 0

h1 := .1

N1 := 10

>

A list of values of the independent variable x at which the corresponding values of the dependent variable y are to be obtained is

> x_list := Array( 1..N1+1, i -> x0 + (i-1)*h1 );

x_list := Array([0., .1, .2, .3, .4, .5, .6, .7, .8, .9, 1.0])

>

Then, the table of approximate solution values computed using Euler's Method is

> dsolve( { ode1, ic1 }, y(x), type=numeric,

>        method=classical, stepsize=h1, output=x_list );

Matrix([[Array([x, y(x)])], [Matrix([[0., 1.], [.1, .800000000000000042], [.2, .640000000000000014], [.3, .512000000000000010], [.4, .409600000000000020], [.5, .327680000000000028], [.6, .262144000000...

>

If the results are to be plotted, then the dsolve and odeplot commands can be used as follows, resulting in Figure 14.1.

> sol := dsolve( { ode1, ic1 }, y(x), type=numeric,

>               method=classical, stepsize=h1 ):

> odeplot( sol, [x,y(x)], 0..1, title="Figure 14.1" );

[Plot]

>

14.B-2 Example 2 (revisited)

The three approximations to y(2) are obtained via

> for k from 1 to 3 do
 sol2 := dsolve( { ode2, ic2 }, y(t), type=numeric, method=classical, stepsize=H2[k] ):

 Y2[k] := eval( y(t), sol2(2) );

 print(` Y2`[k] = Y2[k]);

od:

` Y2`[1] = 2.79760832314891060

` Y2`[2] = 2.71059958025902015

` Y2`[3] = 2.67742503870978908

>

Alternatively, these results are summarized in the following table.

> v0 := < 'h'   | 'N'   | 'Y(2)' >:

> v1 := < H2[1] | N2[1] | Y2[1]  >:

> v2 := < H2[2] | N2[2] | Y2[2]  >:

> v3 := < H2[3] | N2[3] | Y2[3]  >:

> < v0, v1, v2, v3 >;

Matrix([[h, N, Y(2)], [1/2, 2, 2.79760832314891060], [1/4, 4, 2.71059958025902015], [1/8, 8, 2.67742503870978908]])

>

14.C Example 3

The final example illustrates the use of the full range of Maple tools to obtain, visualize, and analyze an approximate solution to an IVP obtained by Euler's Method.

Consider the problem of obtaining a solution to the IVP

> ode3 := diff( y(t) , t ) = sin( y(t) ) ;

> ic3 := y(0) = 1;

ode3 := diff(y(t), t) = sin(y(t))

ic3 := y(0) = 1

> Euler0((t,y)->sin(y),0,1,2,4);

Matrix([[0., 1.], [2., 2.68294196999999990], [4., 3.56841925979999974], [6., 2.74045085539999978], [8., 3.52139036419999973]])

> sol3e(2);
sol3e(4);

sol3e(6);

sol3e(2)

sol3e(4)

sol3e(6)

>

on the interval [0, 8] .

Euler's Method with N = 4 subdivisions yields Figure 14.2, provided odeplot is instructed to plot five points since the initial point must be counted.

> sol3e := dsolve( { ode3, ic3 }, y(t), type=numeric,

>                 method=classical, stepsize=2 ):

> euler_plot := odeplot( sol3e, [t,y(t)], 0..8, style=line,

>                       color=BLUE, numpoints=5 ):

> display( euler_plot, title="Figure 14.2" );

[Plot]

>

To determine if this approximation is reasonable, superimpose this solution on the slope field, as shown in Figure 14.3.

> slope_field := DEplot( ode3, y(t), t=0..8, y=0..4, arrows=SMALL ):

> display( [ slope_field, euler_plot ], title="Figure 14.3" );

[Plot]

>

On the interval [0, 2] the Euler solution does not look too bad. However, on [2, 4] the Euler solution does not follow the slope field and is a much poorer approximation to the true solution. Note also that the Euler solution repeatedly crosses the equilibrium solution y(t) = Pi . To obtain a reasonable approximation on the entire interval using Euler's Method, a smaller stepsize is required.  Figure 14.4 shows the result of computing with a stepsize of 0.5.

> sol3e2 := dsolve( { ode3, ic3 }, y(t), type=numeric,

>                  method=classical, stepsize=0.5 ):

> euler_plot2 := odeplot( sol3e2, [t,y(t)], 0..8, style=line,

>                        color=CYAN, thickness=3, numpoints=17 ):

> display( [ slope_field, euler_plot2 ], title="Figure 14.4" );

[Plot]

>

To complete the evaluation of this approximate solution, the DEplot command is used to include the (Maple-generated approximate) solution curve for this initial condition.  Figure 14.5 shows the Euler solution with stepsize 2 as the blue curve, the Euler solution with stepsize 0.5 as the cyan curve, and the default (adaptive) numeric solution as the brown curve.

> sol_plot := DEplot( ode3, y(t), t=0..8, [ [ic3] ],

>                    arrows=NONE, linecolor=BROWN ):

> display( [ slope_field, sol_plot, euler_plot, euler_plot2 ], title="Figure 14.5" );

[Plot]

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