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Related Rates - Traveling Ships 2

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Related Rates II 

Copyright Maplesoft, a division of Waterloo Maple Inc., 2007 

 

Introduction 

This application is one of a collection of examples teaching Calculus with Maple. These applications use Clickable Calculus? methods to solve problems interactively. Steps are given at every stage of the solution, and many are illustrated using short video clips.  Click on the Image buttons to watch the videos. 

 

The steps in the document can be repeated to solve similar problems. 

 

Problem Statement 

At 1:00 PM a ship traveling at 9 knots sets sail northeast along a line that makes a Typesetting:-mrow(Typesetting:-msup(Typesetting:-mn(angle with a line running due east (see Figure 1).  An hour later, a second ship sets sail due north.  At 11 PM, the distance between the ships is observed to be 126 nautical miles and is increasing at a rate of Typesetting:-mrow(Typesetting:-mfrac(Typesetting:-mn( knots.  How fast is the north-bound ship traveling? 

 

 

Solution 

Drawing-Canvas 

Figure 1: Diagram showing the path of the ships. 

Let Typesetting:-mrow(Typesetting:-mi( be the displacement of the north-bound ship and Typesetting:-mrow(Typesetting:-mi( be the displacement of the ship traveling north-east, at time Typesetting:-mrow(Typesetting:-mi( hours after 2:00 PM. Then the problem states: 

 

Typesetting:-mrow(Typesetting:-mi( 

At 11 PM: 

Typesetting:-mrow(Typesetting:-mi( 

Typesetting:-mrow(Typesetting:-mi( 

 

Table 1: Figure 1 and the information given in the Problem Statement. 

 

The distance between the ships is given by the law of cosines: 

Typesetting:-mrow(Typesetting:-mi( 

`*`(`^`(d(t), 2)) = `+`(`*`(`^`(a(t), 2)), `*`(`^`(b(t), 2)), `-`(`*`(a(t), `*`(b(t))))) (3.1)
 

To find the rate that the distance is increasing, differentiate this equation with respect to t, then evaluate the result at Typesetting:-mrow(Typesetting:-mi( 

To differentiate (3.1), right-click on the equation and select Differentiate>t.  Then right click on the new answer, select Evaluate at a point and choose t=9 as the point. 

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`+`(`*`(2, `*`(d(t), `*`(diff(d(t), t))))) = `+`(`*`(2, `*`(a(t), `*`(diff(a(t), t)))), `*`(2, `*`(b(t), `*`(diff(b(t), t)))), `-`(`*`(diff(a(t), t), `*`(b(t)))), `-`(`*`(a(t), `*`(diff(b(t), t))))) (3.2)
 

Typesetting:-mover(Typesetting:-mo( 

`+`(`*`(2, `*`(d(9), `*`(eval(diff(d(t), t), {t = 9}))))) = `+`(`*`(2, `*`(a(9), `*`(eval(diff(a(t), t), {t = 9})))), `*`(2, `*`(b(9), `*`(eval(diff(b(t), t), {t = 9})))), `-`(`*`(eval(diff(a(t), t), ... (3.3)
 

Substitute the known values from Table 1. In addition, let Typesetting:-mrow(Typesetting:-mi(, the distance travelled by the north-bound ship, and let Typesetting:-mrow(Typesetting:-mi(, the speed of the north-bound ship. 

[Ctrl] -drag a copy of the result above to a new line. Highlight each value to be replaced, and type in the new value. [Enter]. 

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Typesetting:-mrow(Typesetting:-mn( 

3492 = `+`(`*`(2, `*`(x, `*`(y))), 1620, `-`(`*`(90, `*`(y))), `-`(`*`(9, `*`(x)))) (3.4)
 

This gives one equation in Typesetting:-mrow(Typesetting:-mi( and Typesetting:-mrow(Typesetting:-mi(. Find a second equation by evaluating the distance equation at Typesetting:-mrow(Typesetting:-mi(. 

Enter the eqation for distance by entering the equation label ([Ctrl][L]), then press [Enter].  Then right click , select Evaluate at a point and choose t=9 as the point. 

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Typesetting:-mrow(Typesetting:-mi( 

`*`(`^`(d(t), 2)) = `+`(`*`(`^`(a(t), 2)), `*`(`^`(b(t), 2)), `-`(`*`(a(t), `*`(b(t))))) (3.5)
 

Typesetting:-mover(Typesetting:-mo( 

`*`(`^`(d(9), 2)) = `+`(`*`(`^`(a(9), 2)), `*`(`^`(b(9), 2)), `-`(`*`(a(9), `*`(b(9))))) (3.6)
 

 

 

 

 

Substitute the known values from the Table 1, including the definition for Typesetting:-mrow(Typesetting:-mi(. 

[Ctrl]-drag a copy of the result above to a new line. Highlight each value to be replaced, type in the new value, and then press [Enter]. 

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Typesetting:-mrow(Typesetting:-msup(Typesetting:-mn( 

15876 = `+`(`*`(`^`(x, 2)), 8100, `-`(`*`(90, `*`(x)))) (3.7)
 

To find Typesetting:-mrow(Typesetting:-mi( and Typesetting:-mrow(Typesetting:-mi(, solve equation 3492 = `+`(`*`(2, `*`(x, `*`(y))), 1620, `-`(`*`(90, `*`(y))), `-`(`*`(9, `*`(x)))) and 15876 = `+`(`*`(`^`(x, 2)), 8100, `-`(`*`(90, `*`(x)))) simultaneously. 

Juxtapose the equations (3.4) and (3.7) using the label number. Right-click  Solve>Solve 

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Typesetting:-mrow(Typesetting:-mi( 

3492 = `+`(`*`(2, `*`(x, `*`(y))), 1620, `-`(`*`(90, `*`(y))), `-`(`*`(9, `*`(x)))), 15876 = `+`(`*`(`^`(x, 2)), 8100, `-`(`*`(90, `*`(x)))) (3.8)
 

Typesetting:-mover(Typesetting:-mo( 

{x = -54, y = -7}, {y = 16, x = 144} (3.9)
 

 

Since both Typesetting:-mrow(Typesetting:-mi( and Typesetting:-mrow(Typesetting:-mi( need to be non negative, the solution for the north-bound ship can be found above. 

 

 

 

Legal Notice: The copyright for this application is owned by Maplesoft. The application is intended to demonstrate the use of Maple to solve a particular problem. It has been made available for product evaluation purposes only and may not be used in any other context without the express permission of Maplesoft.   

 

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