Important: The solvefor command has been deprecated.  Use the superseding command solve instead.

The solvefor command isolates specified variables (if any) from a set of equations on the left-hand side of a reduced set of equations. If no variables are specified it is essentially equivalent to a call to solve. Answer are returned in a form suitable for use in other commands such as subs and eval.

The original set of equations is formed by collecting the arguments to solvefor into a set of equations. The solve command is applied to the resulting system to produce 0 or more solutions.

If no solution is found this is indicated by an empty list. If more than one solution is found then they are returned as a list of solutions.

Each solution is returned as an equation, or (if more than one equation is involved) as a set of equations in which the variables on the left-hand side do not appear on the right hand side.

Variables may be specified as an index to the procedure name, as in solvefor[x](...).  This indicates that the solutions must include the indicated variables on the left-hand side of the solution equations.

$\mathrm{solvefor}\left(\left\{x^3-y^{2}x+xy=3\,x^2+y^2=1\right\}\right)$

Warning, solvefor is deprecated. Please use solve command.

$\left[\left\{x=\mathrm{RootOf}\left(4{\mathrm{\_Z}}^6-3{\mathrm{\_Z}}^4-12{\mathrm{\_Z}}^3+6\mathrm{\_Z}+9\,\mathrm{index}=1\right)\,y=-\frac{4{\mathrm{RootOf}\left(4{\mathrm{\_Z}}^6-3{\mathrm{\_Z}}^4-12{\mathrm{\_Z}}^3+6\mathrm{\_Z}+9\,\mathrm{index}=1\right)}^5}{3}+{\mathrm{RootOf}\left(4{\mathrm{\_Z}}^6-3{\mathrm{\_Z}}^4-12{\mathrm{\_Z}}^3+6\mathrm{\_Z}+9\,\mathrm{index}=1\right)}^3+2{\mathrm{RootOf}\left(4{\mathrm{\_Z}}^6-3{\mathrm{\_Z}}^4-12{\mathrm{\_Z}}^3+6\mathrm{\_Z}+9\,\mathrm{index}=1\right)}^2-1\right\}\,\left\{x=\mathrm{RootOf}\left(4{\mathrm{\_Z}}^6-3{\mathrm{\_Z}}^4-12{\mathrm{\_Z}}^3+6\mathrm{\_Z}+9\,\mathrm{index}=2\right)\,y=-\frac{4{\mathrm{RootOf}\left(4{\mathrm{\_Z}}^6-3{\mathrm{\_Z}}^4-12{\mathrm{\_Z}}^3+6\mathrm{\_Z}+9\,\mathrm{index}=2\right)}^5}{3}+{\mathrm{RootOf}\left(4{\mathrm{\_Z}}^6-3{\mathrm{\_Z}}^4-12{\mathrm{\_Z}}^3+6\mathrm{\_Z}+9\,\mathrm{index}=2\right)}^3+2{\mathrm{RootOf}\left(4{\mathrm{\_Z}}^6-3{\mathrm{\_Z}}^4-12{\mathrm{\_Z}}^3+6\mathrm{\_Z}+9\,\mathrm{index}=2\right)}^2-1\right\}\,\left\{x=\mathrm{RootOf}\left(4{\mathrm{\_Z}}^6-3{\mathrm{\_Z}}^4-12{\mathrm{\_Z}}^3+6\mathrm{\_Z}+9\,\mathrm{index}=3\right)\,y=-\frac{4{\mathrm{RootOf}\left(4{\mathrm{\_Z}}^6-3{\mathrm{\_Z}}^4-12{\mathrm{\_Z}}^3+6\mathrm{\_Z}+9\,\mathrm{index}=3\right)}^5}{3}+{\mathrm{RootOf}\left(4{\mathrm{\_Z}}^6-3{\mathrm{\_Z}}^4-12{\mathrm{\_Z}}^3+6\mathrm{\_Z}+9\,\mathrm{index}=3\right)}^3+2{\mathrm{RootOf}\left(4{\mathrm{\_Z}}^6-3{\mathrm{\_Z}}^4-12{\mathrm{\_Z}}^3+6\mathrm{\_Z}+9\,\mathrm{index}=3\right)}^2-1\right\}\,\left\{x=\mathrm{RootOf}\left(4{\mathrm{\_Z}}^6-3{\mathrm{\_Z}}^4-12{\mathrm{\_Z}}^3+6\mathrm{\_Z}+9\,\mathrm{index}=4\right)\,y=-\frac{4{\mathrm{RootOf}\left(4{\mathrm{\_Z}}^6-3{\mathrm{\_Z}}^4-12{\mathrm{\_Z}}^3+6\mathrm{\_Z}+9\,\mathrm{index}=4\right)}^5}{3}+{\mathrm{RootOf}\left(4{\mathrm{\_Z}}^6-3{\mathrm{\_Z}}^4-12{\mathrm{\_Z}}^3+6\mathrm{\_Z}+9\,\mathrm{index}=4\right)}^3+2{\mathrm{RootOf}\left(4{\mathrm{\_Z}}^6-3{\mathrm{\_Z}}^4-12{\mathrm{\_Z}}^3+6\mathrm{\_Z}+9\,\mathrm{index}=4\right)}^2-1\right\}\,\left\{x=\mathrm{RootOf}\left(4{\mathrm{\_Z}}^6-3{\mathrm{\_Z}}^4-12{\mathrm{\_Z}}^3+6\mathrm{\_Z}+9\,\mathrm{index}=5\right)\,y=-\frac{4{\mathrm{RootOf}\left(4{\mathrm{\_Z}}^6-3{\mathrm{\_Z}}^4-12{\mathrm{\_Z}}^3+6\mathrm{\_Z}+9\,\mathrm{index}=5\right)}^5}{3}+{\mathrm{RootOf}\left(4{\mathrm{\_Z}}^6-3{\mathrm{\_Z}}^4-12{\mathrm{\_Z}}^3+6\mathrm{\_Z}+9\,\mathrm{index}=5\right)}^3+2{\mathrm{RootOf}\left(4{\mathrm{\_Z}}^6-3{\mathrm{\_Z}}^4-12{\mathrm{\_Z}}^3+6\mathrm{\_Z}+9\,\mathrm{index}=5\right)}^2-1\right\}\,\left\{x=\mathrm{RootOf}\left(4{\mathrm{\_Z}}^6-3{\mathrm{\_Z}}^4-12{\mathrm{\_Z}}^3+6\mathrm{\_Z}+9\,\mathrm{index}=6\right)\,y=-\frac{4{\mathrm{RootOf}\left(4{\mathrm{\_Z}}^6-3{\mathrm{\_Z}}^4-12{\mathrm{\_Z}}^3+6\mathrm{\_Z}+9\,\mathrm{index}=6\right)}^5}{3}+{\mathrm{RootOf}\left(4{\mathrm{\_Z}}^6-3{\mathrm{\_Z}}^4-12{\mathrm{\_Z}}^3+6\mathrm{\_Z}+9\,\mathrm{index}=6\right)}^3+2{\mathrm{RootOf}\left(4{\mathrm{\_Z}}^6-3{\mathrm{\_Z}}^4-12{\mathrm{\_Z}}^3+6\mathrm{\_Z}+9\,\mathrm{index}=6\right)}^2-1\right\}\right]$

$\mathrm{solvefor}\left[t\right]\left(x+y=1\,x-y+zt=3\right)$

$\left\{t=-\frac{2\left(x-2\right)}{z}\,y=1-x\right\}$

$\mathrm{solvefor}\left[y\right]\left(x+y=1\,x-y+zt=3\right)$

$\left\{x=-\frac{zt}{2}+2\,y=\frac{zt}{2}-1\right\}$

$\mathrm{solvefor}\left[z\right]\left(x+y=1\,x-y+zt=3\right)$

$\left\{y=1-x\,z=-\frac{2\left(x-2\right)}{t}\right\}$