Chapter 3: Applications of Differentiation
Section 3.5: Curvature of a Plane Curve
Example 3.5.2
Show that the circle everywhere has constant curvature, that is, show .
Solution
Mathematical Solution
Implicitly differentiate the equation of the circle to obtain :
Obtain and simplify the denominator of :
The final simplification hinges on the positivity of . Note also that the square root of is , which matters because can be both positive and negative along the circle.
Implicitly differentiate to obtain , the numerator of :
Finally, obtain .
Maple Solution
Initialize
Control-drag the equation of the circle. Context Panel: Assign to a Name: C
Obtain
Type the name C and Press the Enter key.
Context Panel: Differentiate≻Implicitly In the dialog that appears (see Figure 3.5.2(a)), set as the dependent variable, remove y from the list of independent variables, and set as the variable of differentiation.
Press the OK button in the dialog.
Figure 3.5.2(a)
Type the name C and press the Enter key.
Context Panel: Differentiate≻Implicitly Set y as the dependent variable, remove y from the list of independent variables, and write for "Differentiate with respect to".
Form and simplify
Using equation labels, write the expression for , then press the Enter key.
Context Panel: Simplify≻Assuming Real
Context Panel: Simplify≻With Side Relations Enter C for Relations in the Specify Relations dialog, then click the OK button.
Control Panel: Simplify≻Assuming Positive
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